Optimal. Leaf size=552 \[ \frac{\tan (e+f x) (d \sec (e+f x))^{5/3} F_1\left (\frac{1}{2};1,\frac{1}{6};\frac{3}{2};\frac{b^2 \tan ^2(e+f x)}{a^2},-\tan ^2(e+f x)\right )}{a f \sec ^2(e+f x)^{5/6}}+\frac{(d \sec (e+f x))^{5/3} \log \left (-\sqrt [3]{b} \sqrt [6]{a^2+b^2} \sqrt [6]{\sec ^2(e+f x)}+\sqrt [3]{a^2+b^2}+b^{2/3} \sqrt [3]{\sec ^2(e+f x)}\right )}{4 b^{2/3} f \sqrt [6]{a^2+b^2} \sec ^2(e+f x)^{5/6}}-\frac{(d \sec (e+f x))^{5/3} \log \left (\sqrt [3]{b} \sqrt [6]{a^2+b^2} \sqrt [6]{\sec ^2(e+f x)}+\sqrt [3]{a^2+b^2}+b^{2/3} \sqrt [3]{\sec ^2(e+f x)}\right )}{4 b^{2/3} f \sqrt [6]{a^2+b^2} \sec ^2(e+f x)^{5/6}}-\frac{\sqrt{3} (d \sec (e+f x))^{5/3} \tan ^{-1}\left (\frac{1}{\sqrt{3}}-\frac{2 \sqrt [3]{b} \sqrt [6]{\sec ^2(e+f x)}}{\sqrt{3} \sqrt [6]{a^2+b^2}}\right )}{2 b^{2/3} f \sqrt [6]{a^2+b^2} \sec ^2(e+f x)^{5/6}}+\frac{\sqrt{3} (d \sec (e+f x))^{5/3} \tan ^{-1}\left (\frac{2 \sqrt [3]{b} \sqrt [6]{\sec ^2(e+f x)}}{\sqrt{3} \sqrt [6]{a^2+b^2}}+\frac{1}{\sqrt{3}}\right )}{2 b^{2/3} f \sqrt [6]{a^2+b^2} \sec ^2(e+f x)^{5/6}}-\frac{(d \sec (e+f x))^{5/3} \tanh ^{-1}\left (\frac{\sqrt [3]{b} \sqrt [6]{\sec ^2(e+f x)}}{\sqrt [6]{a^2+b^2}}\right )}{b^{2/3} f \sqrt [6]{a^2+b^2} \sec ^2(e+f x)^{5/6}} \]
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Rubi [A] time = 0.84942, antiderivative size = 552, normalized size of antiderivative = 1., number of steps used = 16, number of rules used = 11, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.44, Rules used = {3512, 757, 429, 444, 63, 296, 634, 618, 204, 628, 208} \[ \frac{\tan (e+f x) (d \sec (e+f x))^{5/3} F_1\left (\frac{1}{2};1,\frac{1}{6};\frac{3}{2};\frac{b^2 \tan ^2(e+f x)}{a^2},-\tan ^2(e+f x)\right )}{a f \sec ^2(e+f x)^{5/6}}+\frac{(d \sec (e+f x))^{5/3} \log \left (-\sqrt [3]{b} \sqrt [6]{a^2+b^2} \sqrt [6]{\sec ^2(e+f x)}+\sqrt [3]{a^2+b^2}+b^{2/3} \sqrt [3]{\sec ^2(e+f x)}\right )}{4 b^{2/3} f \sqrt [6]{a^2+b^2} \sec ^2(e+f x)^{5/6}}-\frac{(d \sec (e+f x))^{5/3} \log \left (\sqrt [3]{b} \sqrt [6]{a^2+b^2} \sqrt [6]{\sec ^2(e+f x)}+\sqrt [3]{a^2+b^2}+b^{2/3} \sqrt [3]{\sec ^2(e+f x)}\right )}{4 b^{2/3} f \sqrt [6]{a^2+b^2} \sec ^2(e+f x)^{5/6}}-\frac{\sqrt{3} (d \sec (e+f x))^{5/3} \tan ^{-1}\left (\frac{1}{\sqrt{3}}-\frac{2 \sqrt [3]{b} \sqrt [6]{\sec ^2(e+f x)}}{\sqrt{3} \sqrt [6]{a^2+b^2}}\right )}{2 b^{2/3} f \sqrt [6]{a^2+b^2} \sec ^2(e+f x)^{5/6}}+\frac{\sqrt{3} (d \sec (e+f x))^{5/3} \tan ^{-1}\left (\frac{2 \sqrt [3]{b} \sqrt [6]{\sec ^2(e+f x)}}{\sqrt{3} \sqrt [6]{a^2+b^2}}+\frac{1}{\sqrt{3}}\right )}{2 b^{2/3} f \sqrt [6]{a^2+b^2} \sec ^2(e+f x)^{5/6}}-\frac{(d \sec (e+f x))^{5/3} \tanh ^{-1}\left (\frac{\sqrt [3]{b} \sqrt [6]{\sec ^2(e+f x)}}{\sqrt [6]{a^2+b^2}}\right )}{b^{2/3} f \sqrt [6]{a^2+b^2} \sec ^2(e+f x)^{5/6}} \]
Antiderivative was successfully verified.
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Rule 3512
Rule 757
Rule 429
Rule 444
Rule 63
Rule 296
Rule 634
Rule 618
Rule 204
Rule 628
Rule 208
Rubi steps
\begin{align*} \int \frac{(d \sec (e+f x))^{5/3}}{a+b \tan (e+f x)} \, dx &=\frac{(d \sec (e+f x))^{5/3} \operatorname{Subst}\left (\int \frac{1}{(a+x) \sqrt [6]{1+\frac{x^2}{b^2}}} \, dx,x,b \tan (e+f x)\right )}{b f \sec ^2(e+f x)^{5/6}}\\ &=\frac{(d \sec (e+f x))^{5/3} \operatorname{Subst}\left (\int \left (\frac{a}{\left (a^2-x^2\right ) \sqrt [6]{1+\frac{x^2}{b^2}}}+\frac{x}{\left (-a^2+x^2\right ) \sqrt [6]{1+\frac{x^2}{b^2}}}\right ) \, dx,x,b \tan (e+f x)\right )}{b f \sec ^2(e+f x)^{5/6}}\\ &=\frac{(d \sec (e+f x))^{5/3} \operatorname{Subst}\left (\int \frac{x}{\left (-a^2+x^2\right ) \sqrt [6]{1+\frac{x^2}{b^2}}} \, dx,x,b \tan (e+f x)\right )}{b f \sec ^2(e+f x)^{5/6}}+\frac{\left (a (d \sec (e+f x))^{5/3}\right ) \operatorname{Subst}\left (\int \frac{1}{\left (a^2-x^2\right ) \sqrt [6]{1+\frac{x^2}{b^2}}} \, dx,x,b \tan (e+f x)\right )}{b f \sec ^2(e+f x)^{5/6}}\\ &=\frac{F_1\left (\frac{1}{2};1,\frac{1}{6};\frac{3}{2};\frac{b^2 \tan ^2(e+f x)}{a^2},-\tan ^2(e+f x)\right ) (d \sec (e+f x))^{5/3} \tan (e+f x)}{a f \sec ^2(e+f x)^{5/6}}+\frac{(d \sec (e+f x))^{5/3} \operatorname{Subst}\left (\int \frac{1}{\left (-a^2+x\right ) \sqrt [6]{1+\frac{x}{b^2}}} \, dx,x,b^2 \tan ^2(e+f x)\right )}{2 b f \sec ^2(e+f x)^{5/6}}\\ &=\frac{F_1\left (\frac{1}{2};1,\frac{1}{6};\frac{3}{2};\frac{b^2 \tan ^2(e+f x)}{a^2},-\tan ^2(e+f x)\right ) (d \sec (e+f x))^{5/3} \tan (e+f x)}{a f \sec ^2(e+f x)^{5/6}}+\frac{\left (3 b (d \sec (e+f x))^{5/3}\right ) \operatorname{Subst}\left (\int \frac{x^4}{-a^2-b^2+b^2 x^6} \, dx,x,\sqrt [6]{\sec ^2(e+f x)}\right )}{f \sec ^2(e+f x)^{5/6}}\\ &=\frac{F_1\left (\frac{1}{2};1,\frac{1}{6};\frac{3}{2};\frac{b^2 \tan ^2(e+f x)}{a^2},-\tan ^2(e+f x)\right ) (d \sec (e+f x))^{5/3} \tan (e+f x)}{a f \sec ^2(e+f x)^{5/6}}-\frac{(d \sec (e+f x))^{5/3} \operatorname{Subst}\left (\int \frac{1}{\sqrt [3]{a^2+b^2}-b^{2/3} x^2} \, dx,x,\sqrt [6]{\sec ^2(e+f x)}\right )}{\sqrt [3]{b} f \sec ^2(e+f x)^{5/6}}-\frac{(d \sec (e+f x))^{5/3} \operatorname{Subst}\left (\int \frac{-\frac{1}{2} \sqrt [6]{a^2+b^2}-\frac{\sqrt [3]{b} x}{2}}{\sqrt [3]{a^2+b^2}-\sqrt [3]{b} \sqrt [6]{a^2+b^2} x+b^{2/3} x^2} \, dx,x,\sqrt [6]{\sec ^2(e+f x)}\right )}{\sqrt [3]{b} \sqrt [6]{a^2+b^2} f \sec ^2(e+f x)^{5/6}}-\frac{(d \sec (e+f x))^{5/3} \operatorname{Subst}\left (\int \frac{-\frac{1}{2} \sqrt [6]{a^2+b^2}+\frac{\sqrt [3]{b} x}{2}}{\sqrt [3]{a^2+b^2}+\sqrt [3]{b} \sqrt [6]{a^2+b^2} x+b^{2/3} x^2} \, dx,x,\sqrt [6]{\sec ^2(e+f x)}\right )}{\sqrt [3]{b} \sqrt [6]{a^2+b^2} f \sec ^2(e+f x)^{5/6}}\\ &=-\frac{\tanh ^{-1}\left (\frac{\sqrt [3]{b} \sqrt [6]{\sec ^2(e+f x)}}{\sqrt [6]{a^2+b^2}}\right ) (d \sec (e+f x))^{5/3}}{b^{2/3} \sqrt [6]{a^2+b^2} f \sec ^2(e+f x)^{5/6}}+\frac{F_1\left (\frac{1}{2};1,\frac{1}{6};\frac{3}{2};\frac{b^2 \tan ^2(e+f x)}{a^2},-\tan ^2(e+f x)\right ) (d \sec (e+f x))^{5/3} \tan (e+f x)}{a f \sec ^2(e+f x)^{5/6}}+\frac{\left (3 (d \sec (e+f x))^{5/3}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt [3]{a^2+b^2}-\sqrt [3]{b} \sqrt [6]{a^2+b^2} x+b^{2/3} x^2} \, dx,x,\sqrt [6]{\sec ^2(e+f x)}\right )}{4 \sqrt [3]{b} f \sec ^2(e+f x)^{5/6}}+\frac{\left (3 (d \sec (e+f x))^{5/3}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt [3]{a^2+b^2}+\sqrt [3]{b} \sqrt [6]{a^2+b^2} x+b^{2/3} x^2} \, dx,x,\sqrt [6]{\sec ^2(e+f x)}\right )}{4 \sqrt [3]{b} f \sec ^2(e+f x)^{5/6}}+\frac{(d \sec (e+f x))^{5/3} \operatorname{Subst}\left (\int \frac{-\sqrt [3]{b} \sqrt [6]{a^2+b^2}+2 b^{2/3} x}{\sqrt [3]{a^2+b^2}-\sqrt [3]{b} \sqrt [6]{a^2+b^2} x+b^{2/3} x^2} \, dx,x,\sqrt [6]{\sec ^2(e+f x)}\right )}{4 b^{2/3} \sqrt [6]{a^2+b^2} f \sec ^2(e+f x)^{5/6}}-\frac{(d \sec (e+f x))^{5/3} \operatorname{Subst}\left (\int \frac{\sqrt [3]{b} \sqrt [6]{a^2+b^2}+2 b^{2/3} x}{\sqrt [3]{a^2+b^2}+\sqrt [3]{b} \sqrt [6]{a^2+b^2} x+b^{2/3} x^2} \, dx,x,\sqrt [6]{\sec ^2(e+f x)}\right )}{4 b^{2/3} \sqrt [6]{a^2+b^2} f \sec ^2(e+f x)^{5/6}}\\ &=-\frac{\tanh ^{-1}\left (\frac{\sqrt [3]{b} \sqrt [6]{\sec ^2(e+f x)}}{\sqrt [6]{a^2+b^2}}\right ) (d \sec (e+f x))^{5/3}}{b^{2/3} \sqrt [6]{a^2+b^2} f \sec ^2(e+f x)^{5/6}}+\frac{\log \left (\sqrt [3]{a^2+b^2}-\sqrt [3]{b} \sqrt [6]{a^2+b^2} \sqrt [6]{\sec ^2(e+f x)}+b^{2/3} \sqrt [3]{\sec ^2(e+f x)}\right ) (d \sec (e+f x))^{5/3}}{4 b^{2/3} \sqrt [6]{a^2+b^2} f \sec ^2(e+f x)^{5/6}}-\frac{\log \left (\sqrt [3]{a^2+b^2}+\sqrt [3]{b} \sqrt [6]{a^2+b^2} \sqrt [6]{\sec ^2(e+f x)}+b^{2/3} \sqrt [3]{\sec ^2(e+f x)}\right ) (d \sec (e+f x))^{5/3}}{4 b^{2/3} \sqrt [6]{a^2+b^2} f \sec ^2(e+f x)^{5/6}}+\frac{F_1\left (\frac{1}{2};1,\frac{1}{6};\frac{3}{2};\frac{b^2 \tan ^2(e+f x)}{a^2},-\tan ^2(e+f x)\right ) (d \sec (e+f x))^{5/3} \tan (e+f x)}{a f \sec ^2(e+f x)^{5/6}}+\frac{\left (3 (d \sec (e+f x))^{5/3}\right ) \operatorname{Subst}\left (\int \frac{1}{-3-x^2} \, dx,x,1-\frac{2 \sqrt [3]{b} \sqrt [6]{\sec ^2(e+f x)}}{\sqrt [6]{a^2+b^2}}\right )}{2 b^{2/3} \sqrt [6]{a^2+b^2} f \sec ^2(e+f x)^{5/6}}-\frac{\left (3 (d \sec (e+f x))^{5/3}\right ) \operatorname{Subst}\left (\int \frac{1}{-3-x^2} \, dx,x,1+\frac{2 \sqrt [3]{b} \sqrt [6]{\sec ^2(e+f x)}}{\sqrt [6]{a^2+b^2}}\right )}{2 b^{2/3} \sqrt [6]{a^2+b^2} f \sec ^2(e+f x)^{5/6}}\\ &=-\frac{\sqrt{3} \tan ^{-1}\left (\frac{1-\frac{2 \sqrt [3]{b} \sqrt [6]{\sec ^2(e+f x)}}{\sqrt [6]{a^2+b^2}}}{\sqrt{3}}\right ) (d \sec (e+f x))^{5/3}}{2 b^{2/3} \sqrt [6]{a^2+b^2} f \sec ^2(e+f x)^{5/6}}+\frac{\sqrt{3} \tan ^{-1}\left (\frac{1+\frac{2 \sqrt [3]{b} \sqrt [6]{\sec ^2(e+f x)}}{\sqrt [6]{a^2+b^2}}}{\sqrt{3}}\right ) (d \sec (e+f x))^{5/3}}{2 b^{2/3} \sqrt [6]{a^2+b^2} f \sec ^2(e+f x)^{5/6}}-\frac{\tanh ^{-1}\left (\frac{\sqrt [3]{b} \sqrt [6]{\sec ^2(e+f x)}}{\sqrt [6]{a^2+b^2}}\right ) (d \sec (e+f x))^{5/3}}{b^{2/3} \sqrt [6]{a^2+b^2} f \sec ^2(e+f x)^{5/6}}+\frac{\log \left (\sqrt [3]{a^2+b^2}-\sqrt [3]{b} \sqrt [6]{a^2+b^2} \sqrt [6]{\sec ^2(e+f x)}+b^{2/3} \sqrt [3]{\sec ^2(e+f x)}\right ) (d \sec (e+f x))^{5/3}}{4 b^{2/3} \sqrt [6]{a^2+b^2} f \sec ^2(e+f x)^{5/6}}-\frac{\log \left (\sqrt [3]{a^2+b^2}+\sqrt [3]{b} \sqrt [6]{a^2+b^2} \sqrt [6]{\sec ^2(e+f x)}+b^{2/3} \sqrt [3]{\sec ^2(e+f x)}\right ) (d \sec (e+f x))^{5/3}}{4 b^{2/3} \sqrt [6]{a^2+b^2} f \sec ^2(e+f x)^{5/6}}+\frac{F_1\left (\frac{1}{2};1,\frac{1}{6};\frac{3}{2};\frac{b^2 \tan ^2(e+f x)}{a^2},-\tan ^2(e+f x)\right ) (d \sec (e+f x))^{5/3} \tan (e+f x)}{a f \sec ^2(e+f x)^{5/6}}\\ \end{align*}
Mathematica [C] time = 5.83324, size = 276, normalized size = 0.5 \[ -\frac{24 d^2 (a+b \tan (e+f x)) F_1\left (\frac{1}{3};\frac{1}{6},\frac{1}{6};\frac{4}{3};\frac{a-i b}{a+b \tan (e+f x)},\frac{a+i b}{a+b \tan (e+f x)}\right )}{b f \sqrt [3]{d \sec (e+f x)} \left ((a+i b) F_1\left (\frac{4}{3};\frac{1}{6},\frac{7}{6};\frac{7}{3};\frac{a-i b}{a+b \tan (e+f x)},\frac{a+i b}{a+b \tan (e+f x)}\right )+(a-i b) F_1\left (\frac{4}{3};\frac{7}{6},\frac{1}{6};\frac{7}{3};\frac{a-i b}{a+b \tan (e+f x)},\frac{a+i b}{a+b \tan (e+f x)}\right )+8 (a+b \tan (e+f x)) F_1\left (\frac{1}{3};\frac{1}{6},\frac{1}{6};\frac{4}{3};\frac{a-i b}{a+b \tan (e+f x)},\frac{a+i b}{a+b \tan (e+f x)}\right )\right )} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.174, size = 0, normalized size = 0. \begin{align*} \int{\frac{1}{a+b\tan \left ( fx+e \right ) } \left ( d\sec \left ( fx+e \right ) \right ) ^{{\frac{5}{3}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (d \sec \left (f x + e\right )\right )^{\frac{5}{3}}}{b \tan \left (f x + e\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (d \sec \left (f x + e\right )\right )^{\frac{5}{3}}}{b \tan \left (f x + e\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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